Creating a Memory-Mapped File
Mapping a file in memory results in a ByteArray object. To
access the byte array, see Getting Bytes from a ByteBuffer and
Putting Bytes into a ByteBuffer.
try {
File file = new File("filename");
// Create a read-only memory-mapped file
FileChannel roChannel = new RandomAccessFile(file, "r").getChannel();
ByteBuffer roBuf = roChannel.map(FileChannel.MapMode.READ_ONLY, 0, (int)roChannel.size());
// Create a read-write memory-mapped file
FileChannel rwChannel = new RandomAccessFile(file, "rw").getChannel();
ByteBuffer wrBuf = rwChannel.map(FileChannel.MapMode.READ_WRITE, 0, (int)rwChannel.size());
// Create a private (copy-on-write) memory-mapped file.
// Any write to this channel results in a private copy of the data.
FileChannel pvChannel = new RandomAccessFile(file, "rw").getChannel();
ByteBuffer pvBuf = roChannel.map(FileChannel.MapMode.READ_WRITE, 0, (int)rwChannel.size());
} catch (IOException e) {
}
how to read a very large file without using io streams? is ther any other technique